C语言写计算分段函数

#include stdio.h

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#include math.h

int main(void)

{

int repeat, ri;

double x, y;

scanf("%d", repeat);

for(ri = 1; ri = repeat; ri++){

scanf("%lf",x);

y=x=0?sqrt(x):pow(x+1,2)+2*x+1/x;

printf("f(%.2f) = %.2f\n", x, y);

}

}

C语言计算分段函数

1. 代码如下，3）需要实际运行时输入测试

int main(void)

{

double x, y, f;

printf("Please input 2 double number in the form of x y:\n");

scanf("%lf%lf", x, y);

if(x=0 y0)

f = 2*x*x + 3*x +1/(x+y);

else if(x=0 y=0)

f = 2*x*x + 3*x +1/(1+y*y);

else

f = 3*sin(x+y)/(2*x*x) + 3*x + 1;

printf("x=%lf, y=%lf, f(x, y)=%lf\n", x, y, f);

return 0;

}

2.代码如下

#include stdio.h

#includemath.h

int main(void)

{

double x, y, f;

printf("Please input 2 double number in the form of x y:\n");

scanf("%lf%lf", x, y);

if(x=0)

{

if(y0)

f = 2*x*x + 3*x +1/(x+y);

else

f = 2*x*x + 3*x +1/(1+y*y);

}

else

f = 3*sin(x+y)/(2*x*x) + 3*x + 1;

printf("x=%lf, y=%lf, f(x, y)=%lf\n", x, y, f);

return 0;

}

3.代码如下

#include stdio.h

int main(void)

{

int score = 0;

printf("Please input a score between 0-100:\n");

scanf("%d", score);

if(score0 || score100)

printf("Wrong input of score!\n");

else if(score=90 score=100)

printf("A\n");

else if(score=80 score=89)

printf("B\n");

else if(score=70 score=79)

printf("C\n");

else if(score=60 score=69)

printf("D\n");

else

printf("E\n");

return 0;

}

用C语言计算分段函数

#include "stdio.h"

#includemath.h

void main()

{

double x,y,f,h;

printf("请输入x:\n");

scanf("%lf",x);

printf("请输入y:\n");

scanf("%lf",y);

if((x=0)(y0))

f=2*pow(x,2)+3*x+1/x+y;

else if((x=0)(y=0))

f=2*x*x+3*x+1/x+y*y;

else

f=3*sin(x+y)/2/pow(x,2)+3*x+1;

printf("x=%lf,y=%lf,f=%lf\n",x,y,f);

h=pow(x,2);

printf("%lf",h);

}

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